Swiftgram/docs/_docs/asviewcontroller.md

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---
title: ASViewController
layout: docs
permalink: /docs/asviewcontroller.html
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---
`ASViewController` is a direct subclass of `UIViewController`. For the most part, it can be used in place of any `UIViewController` relatively easily.
The main difference is that you construct and return the node you'd like managed as opposed to the way `UIViewController` provides a view of its own.
Consider the following `ASViewController` subclass that would like to use a custom table node as its managed node.
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<span class="language-toggle"><a data-lang="swift" class="swiftButton">Swift</a><a data-lang="objective-c" class = "active objcButton">Objective-C</a></span>
<div class = "code">
<pre lang="objc" class="objcCode">
- (instancetype)initWithModel:(NSArray *)models
{
ASTableNode *tableNode = [[ASTableNode alloc] initWithStyle:UITableViewStylePlain];
if (!(self = [super initWithNode:tableNode])) { return nil; }
self.models = models;
self.tableNode = tableNode;
self.tableNode.dataSource = self;
return self;
}
</pre>
<pre lang="swift" class = "swiftCode hidden">
func initWithModel(models: Array&lt;Model&gt;) {
let tableNode = ASTableNode(style:.Plain)
super.initWithNode(tableNode)
self.models = models
self.tableNode = tableNode
self.tableNode.dataSource = self
return self
}
</pre>
</div>
</div>
The most important line is:
`if (!(self = [super initWithNode:tableNode])) { return nil; }`
As you can see, `ASViewController`'s are initialized with a node of your choosing.